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Voltage Drop Calculations for Electricians (and the Exam)

Voltage drop is one of the few exam calculations that matters every day in the field. Long runs to a garage, a well pump or a parking lot light all need it. Here's the formula, what the NEC actually says about it, and a worked example.

What the NEC says

For general branch circuits and feeders, the NEC's voltage drop guidance is in informational notes. They suggest about 3% on a branch circuit and 5% total for feeder plus branch circuit. Informational notes aren't enforceable on their own, but exam questions often ask you to size for them, and good practice follows them. A few specific articles do make voltage drop mandatory, so read the question.

The formulas

Single-phase: VD = (2 × K × I × L) ÷ CM

Three-phase: VD = (1.732 × K × I × L) ÷ CM

Size (AWG)Circular mils
144,110
126,530
1010,380
816,510
626,240

Worked example

A 120 V, 16 A load, 100 feet one way, on 12 AWG copper.

VD = (2 × 12.9 × 16 × 100) ÷ 6,530 = 6.3 V. 6.3 ÷ 120 = 5.3%, over the 3% suggestion.

Try 10 AWG: (2 × 12.9 × 16 × 100) ÷ 10,380 = 4.0 V = 3.3%. Still a little high. 8 AWG gives about 2.5 V, or 2.1%.

Solving for wire size

Flip the formula: CM = (2 × K × I × L) ÷ allowable VD. With 3% of 120 V = 3.6 V, the example needs at least 11,467 CM, so 8 AWG (16,510 CM) is the next size up that works.

Don't forget

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Learn to Navigate the NEC (2026 NEC edition, 28 pages, PDF). The lookup method, a crosswalk for moved articles, drills, marking system and Massachusetts notes. Written by Tim Hodnicki, Easthampton, MA electrical contractor.

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